Dear P-Light,
I appologize for the delay. I am now teaching myself geometry and calculas for I did not have the opportunity to learn these forms of math in high school. I was lucky to get a chance to learn algebra. After I have finished teaching myself these subjects I believe that I will have the knowlege to convert the theory behind the black hole device into a mathematical statement using calculas. Graphic proofs are great but all of the physics journals I have read are written using calculas to represent mathematically whatever measurement is being discussed in that particular journal. As for the device itself in light of my lack of education I went ahead and contracted it’s development to a research and development firm by the name of Davison and Associates. The device is to be a generator for sale. But the generator operates on the same theory in that increase in electrical current and voltage is obtained by constricting a parallel probagating e and h field to a smaller given space. I am not aware of whether compressing and electric field or an electric field will power output of a generator but I know that focusing a magnetic field to a smaller area increases the strength of the field in that area like sunlight focused through a convex lense. And I believe one way to increase the electrical output of a generator is to increase the field strength of the magnets being used to generate the electricity. So I cannot see why the device will no produce higher electrical voltages at higher amperage. (all parts are powered by dc current)If one tries to focus a magnetic field that is generated by an alternating current the field will decrease in amperage as the field is constricted on acount that the frequency of the field is increased as the field is twisted up. Imagine a spring, if you will, and let each revolution in the helixical spring determine the frequency. If you twist the sring in the one direction the distance between the spring crests and troughs will decrease as the spring is tightened thus increasing the frequency of the spring. As a ac current frequency increases the ac output decreases. I imagine that dc is different. I could be wrong in my interpritation of the ac theorum I just stated.


Edwin G. Schasteen